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Network
- inetnum : 172.232.0.0 - 172.239.255.255
- name : LINODE
- handle : NET-172-232-0-0-1
- status : Reassigned
- created : 2008-04-24
- changed : 2022-12-15
- desc : Geofeed https://ipgeo.akamai.com/linode-geofeed.csv,http://www.linode.com
Owner
- organization : Linode
- handle : LINOD
- address : Array,Philadelphia,PA,19106,US
Technical support
- handle : LNO21-ARIN
- name : Linode Network Operations
- phone : +1-609-380-7100
- email : [email protected]
Abuse
- handle : LAS12-ARIN
- name : Linode Abuse Support
- phone : +1-609-380-7100
- email : [email protected]
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Host Informations
| Host name | 172-233-140-203.ip.linodeusercontent.com |
| IP address | 172.233.140.203 |
| Location | United States |
| Latitude | 37.751 |
| Longitude | -97.822 |
| Timezone | America/Chicago |
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fuxuemingzhu (负雪明烛) · GitHub
Block user. Prevent this user from interacting with your repositories and sending you notifications. Learn more about blocking users.. You must be logged in to block users.
Github.comDA: 10 PA: 14 MOZ Rank: 24
一本神书：《数据密集型应用系统设计》 | 负雪明烛
在购物网站上搜「 数据库 」出来的基本都是某种数据库的用法。. 《数据密集型应用系统设计》这本书，把所有跟「数据」有关的知识点做了剖析、整理、总结，从一个很高的层次把各项技术的共性和区别讲得透彻。. 当我们懂了底层原理之后，就明白了每项 ...
Fuxuemingzhu.cnDA: 15 PA: 6 MOZ Rank: 22
GitHub - fuxuemingzhu/fuxuemingzhu.github.io: …
fuxuemingzhu.github.io. Use Git or checkout with SVN using the web URL. Work fast with our official CLI. Learn more . If nothing happens, download GitHub Desktop and try again. If nothing happens, download GitHub Desktop and try again. If nothing happens, download Xcode and try again. Your codespace will open once ready.
Github.comDA: 10 PA: 36 MOZ Rank: 48
GitHub - fuxuemingzhu/WeChoice: 微信精选 Android …
Fuxuemingzhu/WeChoice. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. dev. Switch branches/tags. Branches Tags. Could not load branches. Nothing to show {{ refName }} default View all branches. Could not load tags. Nothing to show {{ refName }} default. View all tags. 1 branch 0 tags. Code. Clone HTTPS …
Github.comDA: 10 PA: 22 MOZ Rank: 35
GitHub - fuxuemingzhu/Leetcode-Solution-All: 1000篇通 …
About. 1000篇通俗易懂且高质量的 LeetCode 解析，动画题解，套路分析，模板分享. fuxuemingzhu.cn/. algorithms leetcode solutions interview. Readme. MIT license. 71 stars. 3 watching. 8 forks.
Github.comDA: 10 PA: 35 MOZ Rank: 49
负雪明烛的博客_CSDN博客-算法,LeetCode,考研机试-九 …
题目的排列顺序是按照先Easy再Medium再Hard排列的，暂时还没有把题目全部整理完成。后序我会把刷过的所有的题目都整理到这个文档里。如果想看我全部的力扣算法题解，可以看我的题解博客：[fuxuemingzhu.cn](fuxuemingzhu.cn)
Blog.csdn.netDA: 13 PA: 14 MOZ Rank: 32
LeetCode Top 100 Liked 点赞最高的 100 道算法题_负雪明烛的博 …
程序员ITS301 程序员ITS301,编程,java,c语言,python,php,android
Its301.comDA: 14 PA: 31 MOZ Rank: 51
【LeetCode】5942. 找出 3 位偶数 Finding 3-Digit Even …
找出 3 位偶数 Finding 3-Digit Even Numbers_负雪明烛的博客-CSDN博客. 【LeetCode】5942. 找出 3 位偶数 Finding 3-Digit Even Numbers. 负雪明烛 于 23:45:03 发布 208 收藏. 分类专栏： LeetCode 算法 文章标签： leetcode 算法 力扣 偶数 寻找. 版权.
Blog.csdn.netDA: 13 PA: 39 MOZ Rank: 59
[LeetCode] 2095. Delete the Middle Node of a Linked List as the ...
For example, if the chain length is 3, then the chain length / 2 - 1 = 0 is the position of the previous node of the intermediate node. For example, if the chain length is 4, then the chain length / 2 - 1 = 1 is the position of the previous node of the intermediate node. The simple way to delete a list node is to move.next = move.next.next.
Programmer.groupDA: 16 PA: 19 MOZ Rank: 43
【LeetCode】645. Set Mismatch Problem Solving Report (Python)
Note: The given array size will in the range [2, 10000]. The given array's numbers won't have any order. Topic. The normal state of the array is 1~N, but there is a number repeated, which causes another number to be covered.
Blog.katastros.comDA: 18 PA: 2 MOZ Rank: 29
Leetcode-Solution-All/802. Find Eventual Safe States 找到最终的安 …
Note: graph will have length at most 10000. The number of edges in the graph will not exceed 32000. Each graph[i] will be a sorted list of different integers, chosen within the range [0, graph.length - 1].
Github.comDA: 10 PA: 50 MOZ Rank: 40
【LeetCode】506. Relative Ranks Problem Solving Report (Python)
Note: N is a positive integer and won't exceed 10,000. All the scores of athletes are guaranteed to be unique. General idea. Set the three largest positions in an array as the gold, silver and bronze awards, and the other positions are the rankings of the current numbers.
Blog.katastros.comDA: 18 PA: 2 MOZ Rank: 31
动手实现基于协同过滤的电影推荐系统 - 负雪明烛 - 博客园
基于用户的协同过滤算法. 基于用户的协同过滤算法主要包括两个步骤。. (1) 找到和目标用户兴趣相似的用户集合。. (2) 找到这个集合中的用户喜欢的，且目标用户没有听说过的物品推荐给目标用户。. 求用户的相似性矩阵的时候，使用的余弦相似度。. 由于两个 ...
Cnblogs.comDA: 15 PA: 29 MOZ Rank: 56
【LeetCode】1094. Car Pooling 拼车_负雪明烛的博客-程序员宅基 …
程序员宅基地 程序员宅基地，技术文章由你所想念有所思
159.138.37.243DA: 14 PA: 31 MOZ Rank: 58
【LeetCode】309. Best Time to Buy and Sell Stock with Cooldown
【LeetCode】309. Best Time to Buy and Sell Stock with Cooldown 解题报告（Python & C++）_负雪明烛的博客-程序员宅基地. 技术标签： 算法 LeetCode
159.138.37.243DA: 14 PA: 30 MOZ Rank: 58
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